Question

Tìm GTNN: 3x^2-6x+2022

Answer 1

\(=3\left(x^2-2x+674\right)\\ =3\left(x^2-2x+1\right)+673\\ =3\left(x-1\right)^2+673\ge673\forall x\\ \)

Dấu = xảy ra khi

\(x-1=0\\ x=1\)

Vậy GTNN : \(673khix=1\)

Answer 2

\(=3x^2-6x+3+2019=3\left(x-1\right)^2+2019>=2019\)

Dấu '=' xảy ra khi x=1