2: \(B=\dfrac{2\sqrt{x}+\sqrt{x}}{\sqrt{x}\left(\sqrt{x}+3\right)}\cdot\dfrac{x-9}{\sqrt{x}+2}\)
\(=\dfrac{3\sqrt{x}}{\sqrt{x}\left(\sqrt{x}+3\right)}\cdot\dfrac{\left(\sqrt{x}+3\right)\left(\sqrt{x}-3\right)}{\sqrt{x}+2}=\dfrac{3\sqrt{x}-9}{\sqrt{x}+2}\)