\(=\dfrac{2}{2x-\sqrt{2x}}-\dfrac{2}{\sqrt{x}}=\dfrac{\sqrt{2}}{\sqrt{2}x-\sqrt{x}}-\dfrac{2}{\sqrt{x}}\\ =\dfrac{2\sqrt{x}-2\left(2x-\sqrt{2x}\right)}{\sqrt{x}\left(2x-\sqrt{2x}\right)}=\dfrac{2\sqrt{x}-4x+2\sqrt{2x}}{2x\sqrt{x}-\sqrt{2}x}=\dfrac{\sqrt{2}-2\sqrt{2x}+2}{\sqrt{2}x-\sqrt{x}}\)