\(=\left(2\sqrt{3}+\sqrt{3}\right)\left(3\sqrt{3}-\sqrt{3}\right)=3\sqrt{3}\cdot2\sqrt{3}=18\)
\(=\left(\sqrt{12}.\sqrt{27}\right)-\left(\sqrt{12}.\sqrt{3}\right)+\left(\sqrt{3}.\sqrt{27}\right)-\left(\sqrt{3}.\sqrt{3}\right)\)
\(=18-6+9-9\)
\(=12\)