Question

Thực hiện phép tính sau:

b) (2x - 1)(3x + 2)(3 - x)

Answer 1

(2x - 1) (3x +2) (3 - x)

=> ( 6x² - 3x + 4x - 2) (3 - x)

=> (6x² + x - 2) (3 - x)

=> 18x² + 3x - 6 - 6x³ - x² + 2x

=> - (6x³ + 18x² - 5x + 6x)

Answer 2

b, (2x-1)(3x+2)(3-x)

⇔(6x\(^2\)+4x-3x-2)(3-x)

⇔18x\(^2\)-6x\(^2\)+12x-4x\(^2\)+9x+2x

⇒ -6x\(^2\)+14x\(^2\)+23x

Answer 3

\(\left(2x-1\right)\left(3x+2\right)\left(3-x\right)\\ =\left(6x^2+4x-3x-2\right)\left(3-x\right)\\ =18x^2-6x^3+12x-4x^2-9x+3x^2-6+2x\\ =-6x^3+17x^2+5x-6\)