Question

Thự hiện phép tính  \(\dfrac{2}{\sqrt{10}+3}+\dfrac{2}{\sqrt{10}-3}\)

Answer 1

\(\dfrac{2}{\sqrt{10}+3}+\dfrac{2}{\sqrt{10}-3}=\dfrac{2\left(\sqrt{10}-3\right)+2\left(\sqrt{10}+3\right)}{\left(\sqrt{10}-3\right)\left(\sqrt{10}+3\right)}=\dfrac{2\sqrt{10}-6+2\sqrt{10}+6}{\sqrt{10^2}-3^2}=\dfrac{4\sqrt{10}}{10-9}=4\sqrt{10}\)