\(\sqrt{a^2+6a+9}=\sqrt{\left(a+3\right)^2}=\left|a+3\right|=a+3\)
\(\sqrt{a^2+6a+9}=\sqrt{a^2+2.a.3+3^2}=\sqrt{\left(a+3\right)^2}=\left|a+3\right|\)
ĐKXĐ: \(a\ge-3\)
\(\sqrt{a^2+6a+9}=\sqrt{a^2+3.2a+3^2}=\sqrt{\left(a+3\right)^2}=\left|a+3\right|=a+3\)
\(\sqrt{a^2+6a+9}=\left|a+3\right|\)