\(\sqrt{3}\cdot tan2x=3\)
=>\(tan2x=\sqrt{3}\)
=>\(2x=\dfrac{\Omega}{3}+k\Omega\)
=>\(x=\dfrac{\Omega}{6}+\dfrac{k\Omega}{2}\)
\(cos\left(\dfrac{\Omega}{6}+\dfrac{k\Omega}{2}\right)=\left[{}\begin{matrix}\pm\dfrac{\sqrt{3}}{2}\\\pm\dfrac{1}{2}\end{matrix}\right.\)