ĐKXĐ: x>=-1/2
Ta có: \(\sqrt{2x+1}+\sqrt{x+5}=6\)
=>\(\sqrt{2x+1}-3+\sqrt{x+5}-3=0\)
=>\(\frac{2x+1-9}{\sqrt{2x+1}+3}+\frac{x+5-9}{\sqrt{x+5}+3}=0\)
=>\(\left(x-4\right)\left(\frac{2}{\sqrt{2x+1}+3}+\frac{1}{\sqrt{x+5}+3}\right)=0\)
=>x-4=0
=>x=4(nhận)