Question

\(\sqrt{25\left(x-3\right)}\) - 10\(\sqrt{\dfrac{x-3}{25}}\)- 1= 3 + \(\sqrt{x-3}\)

Answer 1

\(\sqrt{25\left(x-3\right)}-10\sqrt{\dfrac{x-3}{25}}-1=3+\sqrt{x-3}\left(đk:x\ge3\right)\)

\(\Leftrightarrow5\sqrt{x-3}-10.\dfrac{1}{5}\sqrt{x-3}-1=3+\sqrt{x-3}\)

\(\Leftrightarrow2\sqrt{x-3}=4\Leftrightarrow\sqrt{x-3}=2\)

\(\Leftrightarrow x-3=4\Leftrightarrow x=7\)

Answer 2

Ta có: \(\sqrt{25\left(x-3\right)}-10\sqrt{\dfrac{x-3}{25}}-1=3+\sqrt{x-3}\)

\(\Leftrightarrow5\sqrt{x-3}-2\sqrt{x-3}-\sqrt{x-3}=4\)

\(\Leftrightarrow2\sqrt{x-3}=4\)

\(\Leftrightarrow x-3=4\)

hay x=7