Xét biểu thức A
\(A=8\left(3^2+1\right)\left(3^4+1\right)...\left(3^{64}+1\right)\)
\(=\left(3^2-1\right)\left(3^2+1\right)\left(3^4+1\right)...\left(3^{64}+1\right)\)
\(=\left(3^4-1\right)\left(3^4+1\right)...\left(3^{64}+1\right)\)
\(...=\left(3^{64}-1\right)\left(3^{64}+1\right)=3^{128}-1\)
Vậy \(A=B\)