Question

Rút gọn phân thức sau:

\(\dfrac{3x^4+18x^3+27x^2}{x^3+5x^2+6x}\)

Answer 1

\(\dfrac{3x^4+18x^3+27x^2}{x^3+5x^2+6x}=\dfrac{3x^2\left(x^2+6x+9\right)}{x\left(x^2+5x+6\right)}=\dfrac{3x^2\left(x+3\right)^2}{x\left(x+2\right)\left(x+3\right)}\)

\(=\dfrac{3x\left(x+3\right)}{x+2}\)

Answer 2

\(a,=\dfrac{3x^2\left(x^2+6x+9\right)}{x\left(x^2+5x+6\right)}=\dfrac{3x^2\left(x+3\right)^2}{x\left(x+3\right)\left(x+2\right)}=\dfrac{3x\left(x+3\right)}{x+2}\\ \)