Đặt \(\sqrt[3]{a}=x;\sqrt[3]{b}=y\)
=>\(Q=\dfrac{x^4+x^2y^2+y^4}{x^2+xy+y^2}\)
\(=\dfrac{x^4+2x^2y^2+y^4-x^2y^2}{x^2+xy+y^2}\)
\(=\dfrac{\left(x^2+y^2\right)^2-\left(xy\right)^2}{x^2+xy+y^2}=\dfrac{\left(x^2-xy+y^2\right)\left(x^2+xy+y^2\right)}{x^2+xy+y^2}\)
\(=x^2-xy+y^2\)
\(=\sqrt[3]{a^2}-\sqrt[3]{ab}+\sqrt[3]{b^2}\)