(a+b).(c+d)-(a+d).(b+c)
=(-c-b).d+b.c+b^2
(a+b).(c+d)-(a+d).(b+c)
=ac+ad+bc+bd-ab-ac-bd-dc
=(ac-ac)+(bd-bd)+(ad-ab)+(bc-dc)
=0+0+a.(d-b)+c.(b-d)
=a.(d-b)+c.(b-d)
Hok tốt
\(\left(a+b\right)\left(c+d\right)-\left(a+d\right)\left(b+c\right)\)
\(=ac+ad+bc+bd-ab-ac-db-dc\)
\(=ad+bc-ab-dc\)
\(=\left(ad-ab\right)+\left(bc-dc\right)\)
\(=a\left(d-b\right)+c\left(b-d\right)\)
\(=a\left(d-b\right)-c\left(d-b\right)\)
\(=\left(a-c\right)\left(d-b\right)\)