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Question

rut gon bieu thuc (x-1)^3-(x+1)^3

Hquynh · Accepted Answer

$=\left[\left(x-1\right)-\left(x+1\right)\right]\left[\left(x-1\right)^2+\left(x-1\right)\left(x+1\right)+\left(x+1\right)^2\right]\
=\left(x-1-x-1\right)\left(x^2-2x+1+x^2-1+x^2+2x+1\right)\
=-2\left(3x^2+1\right)\
=-6x^2-2$Câu trả lời: $=\left[\left(x-1\right)-\left(x+1\right)\right]\left[\left(x-1\right)^2+\left(x-1\right)\left(x+1\right)+\left(x+1\right)^2\right]\
=\left(x-1-x-1\right)\left(x^2-2x+1+x^2-1+x^2+2x+1\right)\
=-2\left(3x^2+1\right)\
=-6x^2-2$

Trần Mạnh Nguyên · Answer

(x−1)3−(x+1)3(x-1)3-(x+1)3                                              Bài làm=(x−1−x−1)[(x−1)2−(x−1)(x+1)+(x+1)2]=(x-1-x-1)[(x-1)2-(x-1)(x+1)+(x+1)2]=−2(x2−2x+1−x2+1+x2+2x+1)=-2(x2-2x+1-x2+1+x2+2x+1)=−2(x2+3)=-2(x2+3)=−2x2−6Xin 1 tickCâu trả lời: (x−1)3−(x+1)3(x-1)3-(x+1)3                                              Bài làm=(x−1−x−1)[(x−1)2−(x−1)(x+1)+(x+1)2]=(x-1-x-1)[(x-1)2-(x-1)(x+1)+(x+1)2]=−2(x2−2x+1−x2+1+x2+2x+1)=-2(x2-2x+1-x2+1+x2+2x+1)=−2(x2+3)=-2(x2+3)=−2x2−6Xin 1 tick

Tòi >33 · Answer

`(x-1)^3 - (x+1)^3 ``=[(x-1)-(x+1)][(x-1)^2 + (x-1)(x+1) +(x+1)^2 ]``=(x-1-x-1)[(x^2 - 2x +1) + x^2 -1 +(x^2 + 2x+1)]``=-2(x^2 -2x+1+x^2 -1 + x^2 + 2x+1)``=-2(3x^2 +1)`Câu trả lời: `(x-1)^3 - (x+1)^3 ``=[(x-1)-(x+1)][(x-1)^2 + (x-1)(x+1) +(x+1)^2 ]``=(x-1-x-1)[(x^2 - 2x +1) + x^2 -1 +(x^2 + 2x+1)]``=-2(x^2 -2x+1+x^2 -1 + x^2 + 2x+1)``=-2(3x^2 +1)`

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