Question

rút gọn biểu thức : B= \(\left(\dfrac{x-7\sqrt{x}+12}{x-4\sqrt{x}+3}\right)\dfrac{\sqrt{x}+3}{\sqrt{x}-3}\)( x≥0,x khác 9)

Answer 1

\(B=\dfrac{x-4\sqrt{x}-3\sqrt{x}+12}{x-3\sqrt{x}-\sqrt{x}+3}\cdot\dfrac{\sqrt{x}+3}{\sqrt{x}-3}\)

\(=\dfrac{\left(\sqrt{x}-4\right)\left(\sqrt{x}-3\right)}{\left(\sqrt{x}-1\right)\left(\sqrt{x}-3\right)}\cdot\dfrac{\sqrt{x}+3}{\sqrt{x}-3}\)

\(=\dfrac{\left(\sqrt{x}-4\right)\left(\sqrt{x}+3\right)}{\left(\sqrt{x}-3\right)\left(\sqrt{x}-1\right)}\)