Trả lời
\(-\left(-a+c-d\right)-\left(c-a+d\right)\)
\(=a-c+d-c+a-d\)
\(=2a-2c\)
\(=2\cdot\left(a-c\right)\)
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Ta có:
-(-a+c-d)-(c-a+d)
=a-c+d-c+a-d
=(a+a)-(c+c)+(d-d)
=2a-2c+0
=2.(a-c)
Hok tốt
Trl :
- ( - a + c - d ) - ( c - a + d )
= a - c + d - c + a - d
= 2a - 2c
= 2 x ( a - c )
\(-\left(-a+c-d\right)-\left(c-a+d\right)\)
\(=a-c+d-c+a-d\)
\(=2a-2c\)
\(=2\left(a-c\right)\)
\(-\left(-a+c-d\right)-\left(c-a+d\right)\)
\(=a-c+d-c+a-d\)
\(=2a-2c\)
\(=2.\left(a-c\right)\)
Chúc bạn học tốt !!!
