Question

phân tích thanh nhân tư

a.x³-6x²+9x

b.a²+b²-zab+a-b

c.4a²+4b²-4a+1

Answer 1

làm ơn giúp em với a.

Answer 2

\(a,=x\left(x^2-6x+9\right)\\ =x\left(x-3\right)^2\\ b,Sửa:a^2+b^2-2ab+a-b\\ =\left(a^2-2ab+b^2\right)+\left(a-b\right)\\ =\left(a-b\right)^2+\left(a-b\right)\\ =\left(a-b\right)\left(a-b+1\right)\\ c,=\left(4a^2-4a+1\right)+4b^2\\ =\left(2a-1\right)^2+4b^2\)

Answer 3

a) \(x^3-6x^2+9x=x\left(x^2-6x+9\right)=x\left(x-3\right)^2\)

b) \(a^2+b^2-2ab+a-b=\left(a-b\right)^2+\left(a-b\right)=\left(a-b\right)\left(a-b+1\right)\)

c) Sửa đề \(4a^2-4b^2-4a+1=\left(4a^2-4a+1\right)-4b^2=\left(2a-1\right)^2-\left(2b\right)^2=\left(2a+2b-1\right)\left(2a-2b-1\right)\)

Answer 4

tham khảo câu a :