Question

Phân tích đa thức thành nhân tử:

4a² - 4b² + 16bc - 16c²

Answer 1

\(=4\left[a^2-\left(b^2-4bc+4c^2\right)\right]\)

\(=4\left[a^2-\left(b-2c\right)^2\right]\)

\(=4\left(a-b+2c\right)\left(a+b-2c\right)\)

Answer 2

\(4a^2-4b^2+16bc-16c^2\)

\(=4a^2-\left(4b^2-16bc+16c^2\right)\)

\(=\left(2a\right)^2-\left[\left(2b\right)^2-2.2b.4c+\left(4c\right)^2\right]\)

\(=\left(2a\right)^2-\left(2b-4c\right)^2\)

\(=\left(2a+2b-4c\right)\left(2a-2b+4c\right)\)

\(=4\left(a+b-c\right)\left(a-b+c\right)\)