Phân tích thành nhân tử
\(8x^3+12x^2+6x+1=\left(2x+1\right)^3\)
\(8x^3-12x^2+6x-1\\ =\left(8x^3-1\right)-\left(12x^2-6x\right)\\ =\left(2x-1\right)\left(4x^2+2x+1\right)-6x\left(2x-1\right)\\ =\left(2x-1\right)\left(4x^2+2x+1-6x\right)\\ =\left(2x-1\right)\left(2x-1\right)^2=\left(2x-1\right)^3\)