\(x^4+2x^2-8\)
\(=x^4+4x^2-2x^2-8\)
\(=x^2\left(x^2+4\right)-2\left(x^2+4\right)=\left(x^2+4\right)\left(x^2-2\right)\)
Sửa đề: \(\left(x^2+2x-1\right)^2-3x\left(x^2+2x-1\right)+2x^2\)
\(=\left(x^2+2x-1\right)^2-x\left(x^2+2x-1\right)-2x\left(x^2+2x-1\right)+2x^2\)
\(=\left(x^2+2x-1\right)\left(x^2+2x-1-x\right)-2x\left(x^2+2x-1-x\right)\)
\(=\left(x^2+x-1\right)\left(x^2+2x-1-2x\right)\)
\(=\left(x^2+x-1\right)\left(x^2-1\right)=\left(x^2+x-1\right)\left(x+1\right)\left(x-1\right)\)
x4+2x2−8x4+2x2−8
=x4+4x2−2x2−8=x4+4x2−2x2−8
=x2(x2+4)−2(x2+4)=(x2+4)(x2−2)=x2(x2+4)−2(x2+4)=(x2+4)(x2−2)
Sửa đề: (x2+2x−1)2−3x(x2+2x−1)+2x2(x2+2x−1)2−3x(x2+2x−1)+2x2
=(x2+2x−1)2−x(x2+2x−1)−2x(x2+2x−1)+2x2=(x2+2x−1)2−x(x2+2x−1)−2x(x2+2x−1)+2x2
=(x2+2x−1)(x2+2x−1−x)−2x(x2+2x−1−x)=(x2+2x−1)(x2+2x−1−x)−2x(x2+2x−1−x)
=(x2+x−1)(x2+2x−1−2x)=(x2+x−1)(x2+2x−1−2x)
=(x2+x−1)(x2−1)=(x2+x−1)(x+1)(x−1)
