Question

phân tích đa thức thành nhân tử 

y⁴-y³+y²-y

(a²+b²)² - 4a²b²

a⁴- b⁴

64m³+8y³

Answer 1

Answer 2

b) \(\left(a^2+b^2\right)^2-4a^2b^2\)

\(=\left(a^2-2ab+b^2\right)\left(a^2+2ab+b^2\right)\)

\(=\left(a-b\right)^2\cdot\left(a+b\right)^2\)

c) \(a^4-b^4=\left(a-b\right)\left(a+b\right)\left(a^2+b^2\right)\)

Answer 3

a) \(y^4-y^3+y^2-y\)

\(=y^3\left(y-1\right)+y\left(y-1\right)\)

\(=y\left(y-1\right)\left(y^2+1\right)\)

d) \(64m^3+8y^3=\left(4m+2y\right)\left(16m^2-8my+4y^2\right)\)