Question

Phân tích đa thức thành nhân tử

a,\(x^4+64\)

b,\(4x^4+1\)

c,\(64x^4+y^4\)

hepl me Toshiro KiyoshiNguyễn Huy TúT.Thùy Ninh

Answer 1

a)\(x^4+64\)

\(=x^4+16x^2+64-16x^2\)

\(=\left(x^2+8\right)^2-\left(4x\right)^2\)

\(=\left(x^2-4x+8\right)\left(x^2+4x+8\right)\)

b)\(4x^4+1\)

\(=4x^4+4x^2+1-4x^2\)

\(=\left(2x^2+1\right)^2-\left(2x\right)^2\)

\(=\left(2x^2-2x+1\right)\left(2x^2+2x+1\right)\)

c)\(64x^4+y^4\)

\(=64x^2+16x^2y^2+y^4-16x^2y^2\)

\(=\left(y^2-8x^2\right)^2-\left(4xy\right)^2\)

\(=\left(y^2-4xy+8x^2\right)\left(y^2+4xy+8x^2\right)\)

Answer 2

https://hoc24.vn/hoi-dap/question/403721.html