Question

Ở hình 32 , biết a // b , \(\widehat{A}\) = 90'( độ ) , \(\widehat{C}\) = 130'( độ ) , tính \(\widehat{B}\) , \(\widehat{D}\)

Hình 32

Answer 1

\(a//b;a\perp AB\Rightarrow b\perp AB\Rightarrow\widehat{B}=90^0\)

\(a//b\Rightarrow\widehat{D}+\widehat{C}=180^0\left(trong.cùng.phía\right)\\ \Rightarrow\widehat{D}=180^0-130^0=50^0\)

Answer 2

a,Ta thấy \(\widehat{B}\) là góc vuông

\(\Rightarrow\widehat{B}=90^o\)

\(\widehat{C}+\widehat{D}=180^o\)(bù nhau)

\(\Rightarrow\widehat{D}=180^o-130^o=50^o\)

Answer 3

Vì a//b (gt)

=> góc A = góc B(slt)

Mà góc A = 90°(gt) 

=> góc B = 90°

Vì a//b(gt)

=> góc C + góc D = 180°(tcp)

=> 130°+ góc D = 180°

góc D = 180°- 130° = 50°

 

Answer 4

Ta có: a// b ⇒ \(\widehat{A}\)= \(\widehat{B}\)( 2 góc đồng vị ) 

⇒\(\widehat{B}\)= 90'

Ta lại có: a//b ⇒ \(\widehat{C}\) + \(\widehat{D}\)= 180'( 2 góc trong cùng phía)

⇒130'+\(\widehat{D}\)= 180'

⇒\(\widehat{D}\)= 50'

 

Answer 5

Do a//b ⇒ \(\widehat{A}+\widehat{B}=180^o\left(2gócTCP\right)\)

            \(\Rightarrow90^o+\widehat{B}=180^o\)

            \(\Rightarrow\widehat{B}=180^o-90^o=90^o\)

Do a//b \(\Rightarrow\widehat{D}+\widehat{C}=180^o\left(2gócTCP\right)\)

             \(\Rightarrow\widehat{D}+130^o=180^o\)

              \(\Rightarrow\widehat{D}=180^o-130^0=50^o\)