\(a,=\left(3-5x\right)\left(3+5x\right)\\ b,=\left(2-x\right)^2\\ c,=\left(3-x+y\right)\left(3+x-y\right)\\ d,=\left(4-x-1\right)\left(4+x+1\right)\\ =\left(3-x\right)\left(5+x\right)\\ e,=\left[5-3\left(x-2\right)\right]\left[5+3\left(x-2\right)\right]\\ =\left(5-3x+6\right)\left(5+3x-6\right)=\left(11-3x\right)\left(3x-1\right)\\ f,=\left(2x-x+2\right)\left(2x+x-2\right)\\ \left(x+2\right)\left(3x-2\right)\\ g,=\left(2x+1-x+2\right)\left(2x+1+x-2\right)\\ =\left(x+3\right)\left(3x-1\right)\)
a: \(=\left(3-5x\right)\left(3+5x\right)\)
b: \(=\left(x-2\right)^2\)
c: \(=\left(3-x+y\right)\left(3+x-y\right)\)
d: \(=\left(4-x-1\right)\left(4+x+1\right)=\left(3-x\right)\left(5+x\right)\)
\(a.9-25x^2=\left(3+5x\right)\left(3-5x\right)\)
\(b.4-4x+x^2=\left(2-x\right)^2\)
\(c.9-\left(x-y\right)^2=\left(3+x-y\right)\left(3-x+y\right)\)
\(d.16-\left(x+1\right)^2=\left(x+5\right)\left(3-x\right)\)
\(e.25-9\left(x-2\right)^2=\left[5+3\left(x-2\right)\right]\left[5-3\left(x-2\right)\right]=\left(3x-1\right)\left(11-3x\right)\)
\(f.4x^2-\left(x-2\right)^2=\left(3x-2\right)\left(x+2\right)\)
\(g.\left(2x+1\right)^2-\left(x-2\right)^2=\left(3x-1\right)\left(x+3\right)\)
`a) 9 -25x^2 =3^2 - (5x)^2 = (3-5x)(3+5x)`
`b)4-4x+x^2 = x^2 -4x+4 = x^2 -2*x*2 +2^2 = (x-2)^2`
`c)9-(x-y)^2 = 3^2 - (x-y)^2 = [9-(x-y)](9+x-y) = (9-x+y)(9+x-y)`
`d)16-(x+1)^2 = 4^2 - (x+1)^2 = [4-(x+1)](4+x+1) = (3-x)(x+5)`
`e)25 -9(x-2)^2 = 5^2 - [3(x-2)]^2 = [5-3(x-2)][5+3(x-2)] `
`= (5-3x+6)(5+3x-6) = (11-3x)*(3x-1)`
`f)4x^2 - (x-2)^2 = [4x-(x-2)][4x+x-2] = (4x-x+2)(5x-2) =(3x+2)(5x-2)`
`g)(2x+1)^2 - (x-2)^2 = [2x+1-(x-2)](2x+1+x-2) = (2x+1-x+2)(3x-1)`
`=(x+3)(3x-1)`
mn ơi ai thấy bài này giúp em được ko ạ,e đang cần gấp lắm
