\(\overrightarrow{EH}=4\overrightarrow{ED}-3\overrightarrow{EF}\)
=>\(\overrightarrow{EH}=4\left(\overrightarrow{EH}+\overrightarrow{HD}\right)-3\left(\overrightarrow{EH}+\overrightarrow{HF}\right)\)
=>\(\overrightarrow{EH}=4\overrightarrow{EH}+4\overrightarrow{HD}-3\overrightarrow{EH}-3\overrightarrow{HF}\)
=>\(4\overrightarrow{HD}=3\overrightarrow{HF}\)
=>\(\overrightarrow{HD}=\dfrac{3}{4}\cdot\overrightarrow{HF}\)
=>H nằm trên DF
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