Question

Mn giúp em 2 câu này vs ah

Answer 1

c: \(\Leftrightarrow\left(x-3\right)\left(x-3-2x-1\right)=0\)

=>(x-3)(x+4)=0

=>x=-4 hoặc x=3

d: \(\Leftrightarrow\left(x^2-1\right)\left(x^2+1\right)-2x\left(x^2-1\right)=0\)

=>(x-1)(x+1)=0

=>x=1 hoặc x=-1

Answer 2

`c, -> (x-3)(x-3-2x-1) = 0`

`-> (x-3)(-x - 4) = 0`

`-> -(x-3)(x+4) = 0`

`->` \(\left[{}\begin{matrix}x=3\\x=-4\end{matrix}\right.\)

`d, (x^2-1)(x^2 -2x+1) = 0`

`-> x = +-1`.