Question

Mn giúp chị tiết với ạ

Answer 1

a: \(Fe+2HCl->FeCl_2+H_2\)

\(Cu+2HCl->CuCl_2+H_2\)

Answer 2

a) Fe + 2HCl --> FeCl₂ + H₂

b) \(n_{H_2}=\dfrac{2,24}{22,4}=0,1\left(mol\right)\)

PTHH: Fe + 2HCl --> FeCl₂ + H₂

_____0,1<---------------------0,1

=> \(\left\{{}\begin{matrix}\%Fe=\dfrac{0,1.56}{12}.100\%=46,67\%\\\%Cu=100\%-46,67\%=53,33\%\end{matrix}\right.\)

c) \(n_{Cu}=\dfrac{12-56.0,1}{64}=0,1\left(mol\right)\)

PTHH: 2Fe + 3Cl₂ --t^o--> 2FeCl₃

_____0,1------------------>0,1

Cu + Cl₂ --t^o--> CuCl₂

0,1------------>0,1

=> \(\left\{{}\begin{matrix}m_{FeCl_3}=0,1.162,5=16,25\left(g\right)\\m_{CuCl_2}=0,1.135=13,5\left(g\right)\end{matrix}\right.\)

d) 

2Fe + 6H₂SO₄ --> Fe₂(SO₄)₃ + 3SO₂ + 6H₂O

0,1------------------------------->0,15

Cu + 2H₂SO₄ --> CuSO₄ + SO₂ + 2H₂O

0,1--------------------------->0,1

=> V_SO2 = (0,1+0,15).22,4 = 5,6 (l)