1:
a: \(A=32,125-\left(6,325+12,125\right)-\left(37+13,675\right)\)
\(=32,125-6,325-12,125-37-13,675\)
\(=20-20-37=-37\)
b: \(B=4,75+\left(-\dfrac{1}{2}\right)^3+0,5^2-3\cdot\dfrac{-3}{8}\)
\(=4,75+0,25-\dfrac{1}{8}+\dfrac{9}{8}\)
=5+1
=6
Bài 2:
a: \(A=2^4\cdot5-\left[131-\left(13-4\right)^2\right]\)
\(=16\cdot5-\left[131-9^2\right]\)
=80-50
=30
b: \(B=2^3+3\cdot\left(\dfrac{1}{2}\right)^0-1+\left[\left(-2\right)^2:\dfrac{1}{2}\right]-8\)
\(=8-8+3-1+4\cdot2\)
=2+8
=10
Bài `2`
\(A=2^4\cdot5-\left[131-\left(13-4\right)^2\right]\\ =16\cdot5-\left(131-9^2\right)\\ =16\cdot5-\left(131-81\right)\\ =16\cdot5-50\\ =80-50=30\\ B=2^3+3\left(\dfrac{1}{2}\right)^0-1+\left[\left(-2\right)^2:\dfrac{1}{2}\right]-8\\ =8+3\cdot1-1+\left(4\cdot2\right)-8\\ =8+3-1+8-8\\ =10\)
\(B2\\ A=2^4.5-\left[131-\left(13-4\right)^2\right]\\ =16.5-\left[131-9^2\right]\\ =80-\left[131-81\right]\\ =80-50=30\\ ---\\ B=2^3+3.\left(\dfrac{1}{2}\right)^0-1+\left[\left(-2\right)^2:\dfrac{1}{2}\right]-8\\ =8+3.1-1+\left[4:\dfrac{1}{2}\right]-8\\ =8+3-1+8-8=10\)
\(B1\\ A=32,125-\left(6,325+12,125\right)-\left(37+13,675\right)\\ =\left(32,125-12,125\right)-\left(6,325+13,675\right)-37\\ =20-20-37\\ =0-37=-37\\ ---\\ B=4,75+\left(-\dfrac{1}{2}\right)^3+0,5^2-3.\dfrac{-3}{8}\\ =\dfrac{19}{4}+\left(-\dfrac{1}{8}\right)+\dfrac{1}{4}+\dfrac{9}{8}\\ =\left(\dfrac{19}{4}+\dfrac{1}{4}\right)+\left(\dfrac{9}{8}-\dfrac{1}{8}\right)\\ =5+1=6\)