\(=-\left(\dfrac{1}{1}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+...+\dfrac{1}{61}-\dfrac{1}{64}\right)=-\dfrac{1}{63}\)
e) \(\dfrac{3}{1.4}\)+\(\dfrac{3}{4.7}\)+\(\dfrac{3}{7.10}\)+...+\(\dfrac{3}{40.43}\)
Tính giá trị biểu thức:
B= \(1-\dfrac{3}{1.4}-\dfrac{3}{4.7}-\dfrac{3}{7.10}-...-\dfrac{3}{2020.2023}\)
cho S= \(\dfrac{3}{1.4}+\dfrac{3}{4.7}+\dfrac{3}{7.10}+...+\dfrac{3}{40.43}+\dfrac{3}{43.46}\)
Hãy chứng tỏ rằng S<1
Tìm x, biết:
\(\dfrac{3}{1.4}\)x + \(\dfrac{3}{4.7}\)x + \(\dfrac{3}{7.10}\)x +...+ \(\dfrac{3}{31.34}\)x = 33
a) \(\dfrac{3}{1.4}\) +\(\dfrac{3}{4.7}\) + \(\dfrac{3}{7.10}\) + ... + \(\dfrac{3}{121.124}\)
b) \(\dfrac{3}{2.3}\) + \(\dfrac{3}{3.4}\) + ... + \(\dfrac{3}{100.101}\)
c) \(\dfrac{1}{1.5}\) + \(\dfrac{1}{5.9}\) + \(\dfrac{1}{9.13}\) + ... + \(\dfrac{1}{401.405}\)
d) \(\dfrac{2}{1.3}\) + \(\dfrac{2}{3.5}\) + \(\dfrac{2}{5.7}\) + ... + \(\dfrac{2}{99.101}\)
Cho \(A=\dfrac{3^2}{1.4}+\dfrac{3^2}{4.7}+\dfrac{3^2}{7.10}+...+\dfrac{3^2}{31.24}\).Giá trị của \(A\) là:
\(A.\dfrac{99}{34}B.3\dfrac{33}{34}C.\dfrac{33}{34}D.\)Tất cả đều sai
giúp!
\(c)\dfrac{11}{1.4}+\dfrac{11}{4.7}+\dfrac{11}{7.10}+...\dfrac{11}{61.63}\)
1.Tính nhanh:16+(27-7.6)-(94-7-27.99)
2.Tính tổng:A=\(\dfrac{2}{1.4}+\dfrac{2}{4.7}+\dfrac{2}{7.10}+...+\dfrac{2}{97.100}\)
So sánh A với 1, biết A= 3/1.4+3/4.7+3/7.10+....+3/61.64+3/64.67
( 31/1.4= 31 trên 3.4)
