\(\left(\dfrac{1}{\sqrt{x}-2}+\dfrac{2}{2\sqrt{x}-x}\right):\left(\dfrac{1}{\sqrt{x}+2}+\dfrac{4}{x-4}\right)\left(đk:x>0,x\ne4\right)\)
\(=\dfrac{\sqrt{x}-2}{x-2\sqrt{x}}:\dfrac{\sqrt{x}-2+4}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}=\dfrac{\sqrt{x}-2}{\sqrt{x}}\)