Question

\(\left(2x+1\right)^3=-0,001\)

\(\left(x-\dfrac{1}{2}\right)^0=0\)

\(\left(\dfrac{1}{16}\right)^x=\left(\dfrac{1}{2}\right)^{10}\)

\(\dfrac{8}{25}=\dfrac{2^x}{5^{x-1}}\)

Answer 1

`(2x+1)^3=-0,001`

`(2x+1)^3=-0,1^3`

`2x+1=-0,1`

`2x=-1,1`

`x=-0,55`

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`(x-1/2)^0=0`

`1=0` (Vô lí)

`=>` Ko có gtr của `x` t/m

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`(1/16)^x=(1/2)^10`

`[(1/2)^4]^x=(1/2)^10`

`(1/2)[4x]=(1/2)^10`

`4x=10`

`x=5/2`

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`8/25=[2^x]/[5^[x-1]]`

`[2^3]/[5^2]=[2^x]/[5^[x-1]]`

`=>{(3=x),(2=x-1):}`

`=>{(x=3),(x=3):}=>x=3`