\(\Leftrightarrow1+3x+3x^2+x^3+1-3x+3x^2-x^3=6\left(x+1\right)^2\)
\(\Leftrightarrow6x^2+2=6\left(x^2+2x+1\right)\)
\(\Leftrightarrow6x^2+2=6x^2+12x+6\)
\(\Leftrightarrow12x=-4\)
\(\Leftrightarrow x=-\dfrac{1}{3}\)
1+3x+3x2+1+1-3x2+3x-1=6(x2+2x+1)
6x2 +2 = 6x2+12x+6
-12x - 4 = 0
=> x = 3