\(11.\left(3x+2\right)^2-\left(3x-5\right)\left(3x+2\right)=0\\ \Leftrightarrow\left(3x+2\right)\left(3x+2-3x+5\right)=0\\ \Leftrightarrow7\left(3x+2\right)=0\\ \Leftrightarrow3x+2=0\\ \Leftrightarrow3x=-2\\ \Leftrightarrow x=-\dfrac{2}{3}\\ 13.3\left(x-1\right)^2+\left(x+5\right)\left(2-3x\right)=-25\\ \Leftrightarrow3\left(x^2-2x+1\right)+\left(-3x^2-15x+2x+10\right)=-25\\ \Leftrightarrow3x^2-6x+3-3x^2-13x+10=-25\\ \Leftrightarrow-19x+13=-25\\ \Leftrightarrow19x=13+25=38\\ \Leftrightarrow x=\dfrac{38}{19}=2\\ 14.\left(x+3\right)^2+\left(x-2\right)^2=2x^2\\ \Leftrightarrow x^2+6x+9+x^2-4x+4=2x^2\\ \Leftrightarrow2x^2+2x+13=2x^2\\ \Leftrightarrow2x+13=0\\ \Leftrightarrow2x=-13\\ \Leftrightarrow x=-\dfrac{13}{2}\)
iúp mình với câu a mình làm rồi ,chỉ làm các câu còn lại hoi
