Question

ko cần giải chi tiết ạ !

Answer 1

Bài 10: \(\dfrac{\left(6x^2y^2z^2-3x^3yz^4+x^2y^4z^3\right)}{2xyz^2}\)

\(=\dfrac{6x^2y^2z^2}{2xyz^2}-\dfrac{3x^3yz^4}{2xyz^2}+\dfrac{x^2y^4z^3}{2xyz^2}\)

\(=3xy-\dfrac{3}{2}x^2z^2+\dfrac{1}{2}xy^3z\)

=>Chọn D

Bài 11:

\(\dfrac{2x^4y-6x^2y^7}{2x^2}=\dfrac{2x^4y}{2x^2}-\dfrac{6x^2y^7}{2x^2}=x^2y-3y^7\)

=>a=1; b=-3

=>a+b=-2

=>Chọn D