Bài 4:
b) \(7x=4y\Rightarrow\dfrac{x}{4}=\dfrac{y}{7}\)
Áp dụng t/c dtsbn:
\(\dfrac{x}{4}=\dfrac{y}{7}=\dfrac{y-x}{4-7}=\dfrac{24}{-3}=-8\)
\(\Rightarrow\left\{{}\begin{matrix}x=\left(-3\right).4=-12\\y=\left(-3\right).7=-28\end{matrix}\right.\)
c) Áp dụng t/c dtsbn:
\(\dfrac{x}{3}=\dfrac{y}{4}=\dfrac{2x}{6}=\dfrac{3y}{12}=\dfrac{2x-3y}{6-12}=\dfrac{24}{-6}=-4\)
\(\Rightarrow\left\{{}\begin{matrix}x=\left(-4\right).3=-12\\y=\left(-4\right).4=-16\end{matrix}\right.\)
Bài 3:
a: Ta có: \(\dfrac{2.5}{7.5}=\dfrac{x}{\dfrac{3}{5}}\)
\(\Leftrightarrow\dfrac{x}{\dfrac{3}{5}}=\dfrac{1}{3}\)
hay \(x=\dfrac{1}{5}\)
b: Ta có: \(\dfrac{5}{6}:x=\dfrac{20}{3}\)
\(\Leftrightarrow x=\dfrac{5}{6}:\dfrac{20}{3}=\dfrac{15}{120}=\dfrac{1}{8}\)