a: \(=\dfrac{1}{27}x^3-\dfrac{1}{2}x^2y+\dfrac{9}{4}xy^2-\dfrac{27}{8}y^3\)
b: \(=\left(\dfrac{3}{2}x-2y\right)^3\)
\(=\dfrac{27}{8}x^3-\dfrac{27}{2}x^2y+18xy^2-8y^3\)
a) (x - 2y)3
b) (2x + y)3
c) (\(\dfrac{1}{3}\)x - 1)3
d) (x + \(\dfrac{1}{3}\)y)3
e) (2x - 3y)3
f) (x2 - 2y)3
g) (\(\dfrac{1}{2}\)x - y)3
phan tich da thuc thanh nhan tu
1. x^3y^3 +x^2y^2+4
2. x^4+y^4+(x+y)^4
3.x^8+x+1
4.x^4+5x^3+10x-4
a, x^3-x^2-4x^2+8x-4
b, 4x^2-25-(2x-5)2x+7
c, x^3+27+(x+3)(x-9)
d, 2x^2-2y^2+5x-5y
e, x^2-y^2-2y-1
phan tich da thuc thanh nhan tu
khai trien cac bieu thuc sau
(2x+y)^2
(x-y/2)^2
(x^2+y/2)(x^2-y/2)
(x-2y)^2(x+2y)^2
(x+y)^2
(x-2y)^2
(xy^2+1)(xy^2-1)
(x+y)^2-4(x-y)+4
Phan tich da thuc thanh nhan tu
1) (2x+1)^2 - (x-1)^2
2) 9(x+3)^2 - 4(x-2)^2
3) 25(2x - y) ^2 - 16(x+2y)^2
4) x^4 + x^3 +x + 1
5) x^3 + 3x^2 + 3x + 1 -8y^3
Phan tich da thuc thanh nhan tu:
x^3 - x + 3x^2y + 3xy^2 + y^3 - y
x^2 + 5x - 6
1.phân tích đa thức thành nhân tử chung:
a.40a^3b^3c^2x+12a^3b^4c^2-20a^4b^5cx
b.(b-2c)(a-b)-(a+b)(2c-b)
c.7x^2-4/31x^3-9x^2y
2.tìm x:
a.8x^2-4x=0
b.5x(x-3)+7(x-3)=0
c.2x^2=x
d.x^3=x^5
e.x^2(x+1)+2x(x+1)=0
g.x(2x-3)-2(3-2x)=0
RUT GON PHAN THUC
\(\frac{y^2-x^2}{x^3-3x^2y+3xy^2-y^3}\)
Phan tich da thuc thanh nhan tu:
1)P= 9(x+3)^2 - 4(x-2)^2
2) P= 25(2x-y)^2 - 16(x+2y)^2
Bài 1: Tính
a) ( 3 + 2x )3
b) ( ½ - y )3
c) ( x – 5 ) ( x2 + 5x + 25 )
d) ( 3x + ½ ) ( 9x2 – 3/2*x +1/4 )
