\(\left\{{}\begin{matrix}\overline{M}_{SO_2,O_2\left(\text{coi là X}\right)}=16.3=48\left(g/mol\right)\\\overline{M}_{SO_2,O_2mới\left(\text{coi là Y}\right)}=16.2,5=40\left(g/mol\right)\end{matrix}\right.\)
Áp dụng sơ đồ đường chéo, ta có:
\(\dfrac{V_{O_2}}{V_X}=\dfrac{M_X-M_Y}{M_Y-M_{O_2}}=\dfrac{48-40}{40-32}=\dfrac{1}{1}\)
`=>` \(V_{O_2}=V_X=10\left(l\right)\)