Ta có: \(n_{Al}=\dfrac{10,8}{27}=0,4\left(mol\right)\)
a, PT: \(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\)
______0,4_________________0,2___0,6 (mol)
a, \(V_{H_2}=0,6.22,4=13,44\left(l\right)\)
b, \(V_{ddAl_2\left(SO_4\right)_3}=\dfrac{0,2}{0,1}=2\left(M\right)\)