\(A=2+\dfrac{1}{\left|x^2+1\right|+2}\le\dfrac{5}{2}\forall x\)
Dấu '=' xảy ra khi x=0
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\(A=2+\dfrac{1}{\left|x^2+1\right|+2}\le\dfrac{5}{2}\forall x\)
Dấu '=' xảy ra khi x=0
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pls help vs dag can gap
/x^2+2021/= -2 +2021
help pls cần gấp
7.(x-1/2)^2=9
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