\(\left(x-\frac{1}{4}\right)^2=\frac{1}{9}\)
\(\left(x-\frac{1}{4}\right)^2=\left(\frac{1}{3}\right)^2\)
\(\Rightarrow\left|x-\frac{1}{4}\right|=\frac{1}{3}\)
\(x-\frac{1}{4}=\frac{1}{3}\)HOẶC \(x-\frac{1}{4}=-\frac{1}{3}\)
\(x=\frac{7}{12}\)HOẶC \(x=-\frac{1}{12}\)
Bùng nổ Saiya: giả vờ hay là ko bt thật thế?
Really, I can answer the question.
\(\left(x-\frac{1}{4}\right)^2=\frac{1}{9}\)
\(\left(x-\frac{1}{4}\right)^2=\frac{1}{3}^2\)
\(=>x-\frac{1}{4}=\frac{1}{3}\)
\(x=\frac{1}{3}+\frac{1}{4}\)
\(x=\frac{7}{12}\)