Question

giúp tớ với ✿

Answer 1

\(x^2=x\)

=>\(x^2-x=0\)

=>x(x-1)=0

=>\(\left[\begin{array}{l}x=0\\ x-1=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x=1\end{array}\right.\)

Answer 2

`x^2 = x`

`x^2 -x = 0`

`x(x- 1 ) = 0`

`x= 0` hoặc `x=1`

Vậy: `x=0;x=1`

Answer 3

\(x^2\) = \(x\)

\(x^2\) - \(x\) = 0

\(x.\left(x-1\right)=0\)

\(\left[\begin{array}{l}x=0\\ x-1=0\end{array}\right.\)

\(\left[\begin{array}{l}x=0\\ x=1\end{array}\right.\)

Vậy \(x\in\) {0; 1}