\(2,\Rightarrow\left|1-x\right|=\dfrac{16}{25}+\dfrac{9}{25}=1\\ \Rightarrow\left[{}\begin{matrix}1-x=1\\x-1=1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=2\end{matrix}\right.\\ 3,\Rightarrow3\left(2-x\right)=4\left(3x-1\right)\\ \Rightarrow6-3x=12x-4\\ \Rightarrow15x=10\Rightarrow x=\dfrac{2}{3}\)
2,⇒|1−x|=1625+925=1⇒[1−x=1x−1=1⇒[x=0x=23,⇒3(2−x)=4(3x−1)⇒6−3x=12x−4⇒15x=10⇒x=23