Question

Giúp mình với

Answer 1

e) Vì \(\left\{{}\begin{matrix}\sqrt{x+5}\ge0\\\left(2x+10\right)^4\ge0\end{matrix}\right.\Rightarrow\sqrt{x+5}+\left(2x+10\right)^4\ge0\)

Dấu bằng xảy ra \(\Leftrightarrow\left\{{}\begin{matrix}\sqrt{x+5}=0\\\left(2x+10\right)^4=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x+5=0\\2x+10=0\end{matrix}\right.\Leftrightarrow x=-5\)

Vậy \(x=-5\)

Answer 2

`\sqrt{x+5}+(2x+10)^4=0`           `ĐK: x >= -5`

Vì `\sqrt{x+5} >= 0 AA x >= -5`

   Và `(2x+10)^4 >= 0`

 `=>{(\sqrt{x+5}=0),((2x+10)^4=0):}`

`<=>{(x+5=0),(2x+10=0):}`

`<=>{(x=-5),(x=-5):}<=>x=-5` (t/m)

Answer 3

Vì `sqrt(x+5) >= 0, (2x+10)^4 >=0 forall x.`

Dấu bằng xảy ra `<=> {(x + 5 = 0), (2x + 10=0):}`

`<=> {(x = -5), (x = -5):}`

`-> x = -5`