\(\dfrac{1}{2}x=\dfrac{1}{2}+\dfrac{3}{5}\\ \)
\(\dfrac{1}{2}x=\dfrac{5}{10}+\dfrac{6}{10}\)
\(\dfrac{1}{2}x=\dfrac{11}{10}\\ x=\dfrac{22}{10}\)
\(x=\dfrac{11}{5}\)
\(\dfrac{1}{2}x-\dfrac{3}{5}=\dfrac{1}{2}\)
\(\Rightarrow\dfrac{1}{2}x=\dfrac{11}{10}\)
\(\Rightarrow x=\dfrac{11}{5}\)
Ta có: \(\dfrac{1}{2}x=\dfrac{1}{2}+\dfrac{3}{5}\)
nên \(x\cdot\dfrac{1}{2}=\dfrac{11}{10}\)
hay \(x=\dfrac{11}{5}\)