Bài 1:
a)
a: Ta có: \(\dfrac{1}{7}>0\)
mà \(0>\dfrac{9}{-4}\)
nên \(\dfrac{1}{7}>\dfrac{9}{-4}\)
Bài 1:
a) So sánh:
b) \(\dfrac{2}{5}=\dfrac{2\cdot7}{5\cdot7}=\dfrac{14}{35}\)
Bài 1:
b) \(\dfrac{2}{3}=\dfrac{-2}{-3}\)(Vì \(\dfrac{2}{3}=\dfrac{2\cdot\left(-1\right)}{3\cdot\left(-1\right)}=\dfrac{-2}{-3}\))
Bài 2:
a) \(\dfrac{-3}{5}-\dfrac{4}{15}=\dfrac{-9}{15}-\dfrac{4}{15}=\dfrac{-13}{15}\)
b) \(\dfrac{-3}{5}+\dfrac{5}{7}=\dfrac{-21}{35}+\dfrac{25}{35}=\dfrac{4}{35}\)
c) -75+52=-(75-52)=-23