1,2 làm rồi
\(3,\\ \Rightarrow\left|3x+2\right|=\dfrac{9}{4}+\dfrac{15}{4}=6\\ \Rightarrow\left[{}\begin{matrix}3x+2=6\left(x\ge-\dfrac{2}{3}\right)\\3x+2=-6\left(x< -\dfrac{2}{3}\right)\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}\left(tm\right)\\x=-\dfrac{8}{3}\left(tm\right)\end{matrix}\right.\)
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