\(\Leftrightarrow\dfrac{2\left(3x-1\right)-3\left(x-2\right)-8}{8}>\dfrac{4\left(5-3x\right)}{8}\)
\(\Leftrightarrow2\left(3x-1\right)-3\left(x-2\right)-8>4\left(5-3x\right)\)
\(\Leftrightarrow6x-2-3x+6-8>20-12x\)
\(\Leftrightarrow15x>24\)
\(\Leftrightarrow x>\dfrac{8}{5}\)
Vậy \(S=\left\{x|x>\dfrac{8}{5}\right\}\)
\(\dfrac{3x-1}{4}-\dfrac{3\left(x-2\right)}{8}-1>\dfrac{5-3x}{2}\)
\(\Leftrightarrow\dfrac{2\left(3x-1\right)}{8}-\dfrac{3\left(x-2\right)}{8}-\dfrac{8}{8}>\dfrac{4\left(5-3x\right)}{8}\)
\(\Leftrightarrow6x-2-3x+6-8>20-12x\)
\(\Leftrightarrow3x-4>20-12x\)
\(\Leftrightarrow3x+12x>20+4\)
\(\Leftrightarrow15x>24\)
\(\Leftrightarrow x>\dfrac{8}{5}\)
Vậy...
