9 C
II Tự Luận
Câu 10
\(\dfrac{3}{4}\times\dfrac{11}{6}=\dfrac{33}{24}\)
\(3+\dfrac{4}{5}=\dfrac{3}{1}+\dfrac{4}{5}=\dfrac{15}{5}+\dfrac{4}{5}=\dfrac{19}{5}\)
câu 9 : C
câu 10 :
3/4 x 11/6 = 11/8
3 + 4/5 = 19/5
\(\dfrac{3}{4}\) x \(\dfrac{11}{6}\) = \(\dfrac{3x11}{4x6}\) = \(\dfrac{33}{24}\)
3 + \(\dfrac{4}{5}\) = \(\dfrac{15}{5}\) + \(\dfrac{4}{5}\) = \(\dfrac{19}{5}\)