Question

Giúp mik với, mik cảm ơn

Answer 1

a) \(n_{CaCO_3}=\dfrac{20}{100}=0,2\left(mol\right)\)

=> \(n_{CaCl_2}=0,2\left(mol\right)\)

=> \(m_{CaCl_2}=0,2.111=22,2\left(g\right)\)

b) \(n_{CaCO_3}=\dfrac{5}{100}=0,05\left(mol\right)\)

=> \(n_{CO_2}=0,05\left(mol\right)\)

=> \(V_{CO_2}=0,05.22,4=1,12\left(l\right)\)

c) \(n_{CO_2}=\dfrac{2,24}{22,4}=0,1\left(mol\right)\)

=> \(n_{HCl}=0,2\left(mol\right)\)

=> \(m_{HCl}=0,2.36,5=7,3\left(g\right)\)